从多个输入生成循环

Question

I am trying to generate a list of 1000 houses based on the given inputs of 2 houses ie House_1=[143.5689855, -38.328956999999996] and House_2=[143.5692555, -38.328993] . The difference of these houses will be added to next subsequent houses as shown in below script.

from arcgis.geocoding import reverse_geocode
import pprint

House_1=[143.5689855, -38.328956999999996]
House_2=[143.5692555, -38.328993]


latitude_diff = House_2[0] - House_1[0]
longitude_diff= House_2[1] - House_1[1]



House_3=[House_2[0]+latitude_diff ,House_2[1]+longitude_diff]
pprint.pprint(House_3)

House_4=[House_3[0]+latitude_diff ,House_3[1]+longitude_diff]
pprint.pprint(House_4)

House_5=[House_4[0]+latitude_diff ,House_4[1]+longitude_diff]
pprint.pprint(House_5)
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.
.
.
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House_1000=[House_999[0]+latitude_diff ,House_999[1]+longitude_diff]
pprint.pprint(House_1000)

• As I have used a manual process to generate a list of 3 houses ie House_3, House_4, House_5 .How to generate a loop that will automatically iterate for 1000 houses and output the required results?

Answer 1

Maybe go through the Python tutorial at least once? https://docs.python.org/3/tutorial/controlflow.html#the-range-function

Answer 2

So house_3 is latitude is House_2[0]+1* latitude_diff and house_4 latitude is House_2[0] + 2 * latitude_diff

So you can do a list comprehension -

houses = [House_1, House_2]
for i in range(1, num_houses):
    curr_house = [House_2[0] + i* latitude_diff, House_2[1] + i* longitude_diff]
    pprint.pprint(curr_house)
    houses.append(curr_house)

Answer 3

Houses = [0]*(1000)
Houses[0], Houses[1] = [143.5689855, -38.328956999999996], [143.5692555, -38.328993]
for i in range(2, 1000):
    latitude_diff = Houses[i-1][0] - Houses[i-2][0]
    longitude_diff= Houses[i-1][1] - Houses[i-2][1]
    temp = [Houses[i-1][0]+latitude_diff, Houses[i-1][1]+longitude_diff]

    Houses[i] = temp

Try this :)