如何在满足给定条件的字符串列表列表中返回计算字符串总数的整数列表？

Question

I am trying to get a list of integers that return the number of strings in a list of list of list of strings which is not alphabet. eg:

count_number([[['B0', 'N1','C']], [['AT', '1', 'K']]])

This should give me a result of

[2,1]

What I tried is below: I've only managed to get the total number of strings in the whole list.

count = 0
    for sublist in List1:
        for words in sublist:
            for item in words:
                if not item.isalpha():
                    count +=1
return count

How to turn this into a list of int? Any help will be appreciated.

Answer 1

you can use a regular expression:

import re

l = [[['B0', 'N1','C']], [['AT', '1', 'K']]]

[sum(bool(re.search('[^a-zA-Z]', w)) for w in e) for i in l for e in i]

output:

[2, 1]

Answer 2

Please check this.

def count_number(List1):
    out_put_list = []
    for sublist in List1:
        for words in sublist:
            count = 0
            for item in words:
                if not item.isalpha():
                    count +=1
            out_put_list.append(count)
    return out_put_list


print(count_number([[['B01', 'N1','C1'], ['B01', 'N1','C1']], [['AT1', '1', 'K']]]))

Output:

[3, 3, 2]