使用 sed 在 bash 脚本中删除包含精确字符串的行

Question

I'm trying to run a bash script that removes lines from a file with only the specific string I pass to it, " /home/ken/sed.txt ".

Current script which does nothing:

#!/bin/bash

script="\\/home\\/ken\\/sed.txt"

sed -i "/\<$script\>/d" /home/ken/sed.txt

This deletes all rows:

#!/bin/bash

script="\\/home\\/ken\\/sed.txt"

sed -i "/$script/d" /home/ken/sed.txt

The file:

1 1 1 1 1 /home/ken/sed.txt
6 6 6 6 6 /home/ken/sed.txt
2 2 2 2 2 /home/ken/sed.txt
6 6 6 6 6 /home/ken/sed.txt
3 3 3 3 3 /home/ken/sed.txt
3 3 3 3 3 /home/ken/sed.txt
5 5 5 5 5 /home/ken/sed.txt
1 1 1 1 1 a/home/ken/sed.txt
6 6 6 6 6 a/home/ken/sed.txt
2 2 2 2 2 a/home/ken/sed.txt
6 6 6 6 6 a/home/ken/sed.txt
3 3 3 3 3 a/home/ken/sed.txt
3 3 3 3 3 a/home/ken/sed.txt
5 5 5 5 5 a/home/ken/sed.txt

Desired outcome:

1 1 1 1 1 a/home/ken/sed.txt
6 6 6 6 6 a/home/ken/sed.txt
2 2 2 2 2 a/home/ken/sed.txt
6 6 6 6 6 a/home/ken/sed.txt
3 3 3 3 3 a/home/ken/sed.txt
3 3 3 3 3 a/home/ken/sed.txt
5 5 5 5 5 a/home/ken/sed.txt

Any assistance would be greatly appreciated.

Answer 1

script='/home/ken/sed.txt'
sed -n "\|\b$script|p" file

Output:

1 1 1 1 1 a/home/ken/sed.txt
6 6 6 6 6 a/home/ken/sed.txt
2 2 2 2 2 a/home/ken/sed.txt
6 6 6 6 6 a/home/ken/sed.txt
3 3 3 3 3 a/home/ken/sed.txt
3 3 3 3 3 a/home/ken/sed.txt
5 5 5 5 5 a/home/ken/sed.txt

I switched from // p to \\||p to avoid escaping / .

From man sed :

\\cregexpc : Match lines matching the regular expression regexp. The c may be any character.

See: \\b

Answer 2

As usual when wanting to edit a file in place, I recommend ed over sed -i :

#!/bin/sh
script=" /home/ken/sed.txt"
ed -s sed.txt <<EOF
g!$script!d
w
EOF

Note the addition of a space in your $script variable, to avoid matching the a/home/ken/sed.txt lines. Without that, every line in your example file is deleted, as you've seen.

Answer 3

Why is sed needed? I think you could just grep with the "--fixed-strings" and the "--invert-match" option:

$ fgrep -v ' /home/ken/sed.txt' file.txt
1 1 1 1 1 a/home/ken/sed.txt
6 6 6 6 6 a/home/ken/sed.txt
2 2 2 2 2 a/home/ken/sed.txt
6 6 6 6 6 a/home/ken/sed.txt
3 3 3 3 3 a/home/ken/sed.txt
3 3 3 3 3 a/home/ken/sed.txt
5 5 5 5 5 a/home/ken/sed.txt

grep -F -v ' /home/ken/sed.txt' file.txt