在同一行执行 2 个 bash 命令

Question

I made a bash script to output the content for the *txt files and to print also the name of the file executed on the same line. But for no reason the first line has only the output and the next line has the name of the first output + the output of the next file. How can I have the file name + output ?

for i in *.txt; do cat "$i" && echo -n "$i"; done

Outputs:

ignore
alex.txt11111
alex1.txtda
alex2.txtnu
alex3.txt

Correct would be

alex.txt ignore; alex1.txt 11111; alex2.txt da; alex3.txt nu

Answer 1

You are printing the contents of the file first, then printing its name without a newline ( echo -n ). You should do the opposite: print the name without a newline, but with an extra space at the end, then print the contents of the file.

for f in *.txt; do
    echo -n "$f "
    cat "$f"
done