查询结果并显示在网页上（嵌套数组）

Question

    {% for i in coupontesting %}
    <center>

        <div class="rectangle">
    <span class="right">Store Link</span><span class="left">{{ i.seller_store_name   }}</span>
    <div class="coupon-frame">
                        <div class="coupon-left-div coupon-align-center">
                            <div style="padding: 1.125rem;border-left: 1px solid #d4d4d4;">
                                <div style="position:relative;">
                                    <div class="coupon-left-img-div text-center coupon-align-center orange pt-32">
                    <span class="bold-18">{{ i.name }}</span>
                                    </div>
                                </div>
                            </div>
                            <div class="coupon-ticket-frame">
                                <div class="coupon-ticket-frame-style">
                                    <div class="oupon-ticket-frame-line"></div>
                                </div>
                            </div>
                        </div>
                        <div class="coupon-right-div coupon-align-center">
                {{ i.coupon_code }}
                        </div>

            <div class="coupon-right-div coupon-align-center">
                <button> Use Now </button>
            </div>
    </div>
    <br><br>
    </div>
    </center>
{% endfor %}

Above is the view page

Below is my query from Model Page

   $query = $this->db->query("SELECT * FROM coupon c INNER JOIN coupon_customer cc ON c.coupon_id = cc.coupon_id LEFT JOIN coupon_store cs ON c.coupon_id = cs.seller_store_id LEFT JOIN seller_store ss ON c.seller_store_id = ss.seller_store_id WHERE cc.customer_id = $customer_id AND c.date_end > NOW() ");

       if ($query->num_rows) {
            return $query->rows;
        } else {
            return 0;
        }

Table Structure

Table: coupon
 coupon_id(PK)   name   coupon_code  date_start   date_end  



Table: coupon_customer 
coupon_id(FK)    customer_id(FK)



Table: coupon_store
 coupon_store_id(PK)    coupon_id(FK)    seller_store_id(FK)



Table: seller_store
 seller_store_id(PK)    seller_store_name    seller_id(FK)

 Table: seller
 seller_id(FK)     seller_name   seller_email

 Table: customer
 customer_id(PK)    customer_name customer_email  

Everything works fine , but i wanted to ask is there anyway to "grouping the same seller store together ? Image : https://prnt.sc/rnjbbf (Result from my code)

What i wanted: https://prnt.sc/rnjbqs

If same store then it would group together instead of new line showing the store name again

Answer 1

Assuming a query result set like this (I removed most of the fields for brevity):

$rows = [
    ['seller_store_id' => 1, 'seller_store_name' => 'Foodlama', 'seller_id' => 11, 'coupon_id' => 6322],
    ['seller_store_id' => 2, 'seller_store_name' => 'BlueFood Market', 'seller_id' => 33, 'coupon_id' => 555],
    ['seller_store_id' => 2, 'seller_store_name' => 'BlueFood Market', 'seller_id' => 33, 'coupon_id' => 7787],
];

You can then reformat that result set to be grouped by the store:

$reformatted = [];
foreach ($rows as $row) {
    // here we get all the other key => value pairs that aren't used for grouping
    $nonStoreInfo = array_filter($row, function ($key) {
        return $key !== 'seller_store_id' && $key !== 'seller_store_name' && $key !== 'seller_id';
    }, ARRAY_FILTER_USE_KEY);
    /*
     * We have to manually add any data that is common for the group.
     *
     * Here we overwrite it with each iteration to avoid unnecessary conditional statements
     * (checking if the key exists and has a value). It's cleaner and more concise like this.
     * It doesn't matter because it is the same for every group anyway.
    */
    $reformatted[$row['seller_store_id']]['seller_store_name'] = $row['seller_store_name'];
    $reformatted[$row['seller_store_id']]['seller_id'] = $row['seller_id'];
    $reformatted[$row['seller_store_id']]['coupons'][] = $nonStoreInfo;
}

Note that I made a guess about seller_id . If it can be different for any seller_store_id , then you have to remove it from the array_filter callback and also remove the manual assignment $reformatted[$row['seller_store_id']]['seller_id'] = $row['seller_id']; . Likewise, if you need to add something to the group, you'd have to add the key comparison in array_filter and add the manual assignment.

This will ultimately output an array like this:

Array (
    [1] => Array (
        [seller_store_name] => Foodlama
        [seller_id] => 11
        [coupons] => Array (
            [0] => Array (
                [coupon_id] => 6322
            )
        )
    )
    [2] => Array (
        [seller_store_name] => BlueFood Market
        [seller_id] => 33
        [coupons] => Array (
            [0] => Array (
                [coupon_id] => 555
            )
            [1] => Array (
                [coupon_id] => 7787
            )
        )
    )
)

Now in your template you can iterate the top level (stores) and then iterate the coupons within the stores. You can play around with the array structure and the exact data you need in the group to fit your needs.