努力根据模式删除单词（R 中的文本分析）

Question

I'm new to text analysis. I have been struggling with a particular problem in R this past week. I am trying to figure out how to remove or replace all variations of a word in a string. For example, if the string is:

test <- c("development", "develop", "developing", "developer", "apples", "kiwi")

I want the end output to be:

"apples", "kiwi"

So, basically, I'm trying to figure out how to remove or replace all words beginning with "^develop". I have tried using str_remove_all in the stringr package using this expression:

str_remove_all(test, "^dev")

But the end result was this:

"elopment", "elop", "eloping", "eloper", "apples", "kiwi"

It only removed parts of the word that matched the beginning expression "dev", whereas I want to remove the entire word if it matches the beginning of "dev".

Thanks!

Answer 1

过滤器（函数（x）！any（grepl（“开发”，x）），测试）

Answer 2

Use grep with invert:

grep("^develop", test, invert = TRUE, value = TRUE)
## [1] "apples" "kiwi"  

or negate grepl:

ok <- !grepl("^develop", test)
test[ok]

or remove develop and then retrieve those elements that have not changed:

test[sub("^develop", "", test) == test]

Answer 3

通过stringr ，您可以执行以下操作：

stringr::str_subset(test, "^dev", negate = TRUE)