大于或不等于

Question

My code here

if (parent4 && parent5 && parent6 && (_state[tree][parent4]) + (_state[tree][parent5]) + (_state[tree][parent6]) !== 8) {
  return false;
} else {
  return true;
}

It works, and has some of the elements I want, namely that if the sum of the three _states !== 8 , it returns false .

I'll try to explain the logic I'm trying to achieve as simply as I can:

if par4 + par5 + par6 !>= 8
  return false

if par4 + par5 !>= 8
  return false

if par4 OR par5 OR par6 !>= 8
  return false

else
  return true

I abbreviated the code for simplicity and ease of understanding.

Swapping around return false and return true and changing it to >= doesn't work, because for all elements, even ones I don't mention here, it needs to go to return true by default.

Answer 1

How about this?

if (parent4 && parent5 && parent6) {
    if ((_state[tree][parent4] + _state[tree][parent4] + _state[tree][parent4]) !== 8) {
        return false;
    } else {
        return true;
    }
}

Or in a one-liner:

if (parent4 && parent5 && parent6 && (_state[tree][parent4] + _state[tree][parent4] + _state[tree][parent4]) !== 8) {
    return false;
} else {
    return true;
}