python语音识别中的AttributeError

Question

import speech_recognition as sr

r = sr.Recognizer()

with sr.Microphone as source:
   print("Say something")
   audio = r.listen(source)
   voice_data = r.recognize_google(audio)
   print(voice_data)

I am trying to compiling this code but it gives error like this :-

Exception has occurred: AttributeError
__enter__
File "C:\Users\admin\Desktop\text to speech\speech to text.py", line 5, in 
<module>
with sr.Microphone as source:

Answer 1

Every object used in a context manager, should have an __enter__ method and an __exit__ method implemented in its class. The object you are using, sr.Microphone , is an instance of a class that doesn't implement them. To solve this, you should either not use a context manager (don't use the with ), or implement the __enter__ and __exit__ methods for sr.Microphone 's class. You can find a detailed explanation about context managers in the Python documentation, or a shorter one here .

Answer 2

You just need to use sr.Microphone() you've forgot paranthesis. Remember microphone is a method.

Answer 3

It looks like you have incorrect intention. Try running after fixing indentaion:

import speech_recognition as sr

r = sr.Recognizer()

with sr.Microphone as source:
  print("Say something")
  audio = r.listen(source)
  voice_data = r.recognize_google(audio)
  print(voice_data)

Answer 4

As @motyzk answered, the context manager should have an enter method and an exit method implemented in its class. But I believe sr.Microphone already have it. Please check if you have installed all the required libraries

Answer 5

I know this is kind of late, but try using sr.Microphone() instead of sr.Microphone

>>> import speech_recognition as sr
>>> type(sr.Microphone)
<class 'type'>
>>> type(sr.Microphone())
<class 'speech_recognition.Microphone'>

Here you can see the difference between sr.Microphone() and sr.Microphone , as one is a type, and one is an actual instance of that type.

The type itself doesn't have methods for use in a context manager, but an instance of the class does.