用 sed 替换字符串的一部分

Question

I have a with location:

/Users/spotter/Downloads

and within the Downloads folder there are two files:

test1.txt and test2.txt .

I want to write a shell script to save all the files to a list with a line like this:

file_list="$(ls /Users/spotter/Downloads)"

and echo $file_list will return:

/Users/spotter/Downloads/test1.txt /Users/spotter/Downloads/test2.txt

However I want to change part of the dirname. Particularly I want to change the /Users/spotter part to gs://my_bucket

I tried this like so:

file_list="$(ls /Users/spotter/Downloads | while read path; do dirname "$path" | sed -i "s|/Users/spotter|gs://my_bucket|g"; done)"

which returns:

sed: no input files

when I do echo $file_list I want this to be the output:

gs://my_bucket/Downloads/test1.txt

gs://my_bucket/Downloads/test2.txt

EDIT:

I MUST use ls and I need to keep the entire string replacement within the single list at the end somehow or another.

Answer 1

With GNU find:

file_list=$(find /Users/spotter/Downloads/ -type f -printf 'gs://my_bucket/Downloads/%f\n')

or only with bash:

cd /Users/spotter/Downloads/
file_list=$(for i in *.txt; do echo "gs://my_bucket/Downloads/$i"; done)

Answer 2

如果您可以从 ls 移动到 find 并希望坚持使用 sed：

file_list=$(find /Users/spotter/Downloads -type f | sed 's|/Users/spotter/|gs://my_bucket/|g')