[英]Cox proportional hazard model
I am trying to run Cox proportional hazard model on a data of 4 groups.我正在尝试对 4 个组的数据运行 Cox 比例风险模型。 Here's the data:这是数据:
I am using this code:我正在使用此代码:
time_Allo_NHL<- c(28,32,49,84,357,933,1078,1183,1560,2114,2144)
censor_Allo_NHL<- c(rep(1,5), rep(0,6))
time_Auto_NHL<- c(42,53,57,63,81,140,176,210,252,476,524,1037)
censor_Auto_NHL<- c(rep(1,7), rep(0,1), rep(1,1), rep(0,1), rep(1,1), rep(0,1))
time_Allo_HOD<- c(2,4,72,77,79)
censor_Allo_HOD<- c(rep(1,5))
time_Auto_HOD<- c(30,36,41,52,62,108,132,180,307,406,446,484,748,1290,1345)
censor_Auto_HOD<- c(rep(1,7), rep(0,8))
myData <- data.frame(time=c(time_Allo_NHL, time_Auto_NHL, time_Allo_HOD, time_Auto_HOD),
censor=c(censor_Allo_NHL, censor_Auto_NHL, censor_Allo_HOD, censor_Auto_HOD),
group= rep(1:4,), each= )
str(myData)
The problem is each group has different number of observations.问题是每个组都有不同数量的观察。 What I should modify in the code :我应该在代码中修改什么:
myData <- data.frame(time=c(time_Allo_NHL, time_Auto_NHL, time_Allo_HOD, time_Auto_HOD),
censor=c(censor_Allo_NHL, censor_Auto_NHL, censor_Allo_HOD,
censor_Auto_HOD), group= rep(1:4,), each= )
Instead of writing each=#
so I can run the code properly in order to complete doing the Cox proportional hazard model?而不是编写each=#
以便我可以正确运行代码以完成 Cox 比例风险模型?
Then I have attempted to run a Cox proportional hazard model using the following code:然后我尝试使用以下代码运行 Cox 比例风险模型:
library(survival)
for(i in 1:43){
if (myData$group[i]==2)
myData$Z1[i]<-1
else myData$Z1[i]<-0
}
for(i in 1:43){
if (myData$group[i]==3)
myData$Z2[i]<-1
else myData$Z2[i]<-0
}
for(i in 1:43){
if (myData$group[i]==4)
myData$Z3[i]<-1
else myData$Z3[i]<-0
}
myData
Coxfit<-coxph(Surv(time,censor)~Z1+Z2+Z3, data = myData)
summary(Coxfit)
This is all I got.这就是我所得到的。 There's no valuse!!没有价值!!
Next, I want to test for an interaction between type of transplant and disease type using main effects and interaction terms.接下来,我想使用主效应和交互项来测试移植类型和疾病类型之间的交互作用。
The code I'm going to use:我要使用的代码:
n<-length(myData$time)
n
for (i in 1:n){
if (myData$(here?)[i]==2)
myData$W1[i] <-1
else myData$W1[i]<-0
}
for (i in 1:n){
if (myData$(here?)[i]==2)
myData$W2[i] <-1
else myData$W2[i]<-0
}
myData
Coxfit.W<-coxph(Surv(time,censor)~W1+W2+W1*W2, data = myData)
summary(Coxfit.W)
I'm not sure what it should be written in here (myData$(here?)
from the above code.我不确定上面的代码应该在这里写什么(myData$(here?)
。
This looks like the bone marrow transplant study at Ohio State University.这看起来像俄亥俄州立大学的骨髓移植研究。
As you mentioned, each group has different numbers of observations per group.正如您所提到的,每个组都有不同数量的观察。 I would consider binding the rows from each subgroup together in the end.最后我会考虑将每个子组的行绑定在一起。
First, would create a data frame for each group.首先,将为每个组创建一个数据框。 I would add a column indicating which group they belonged to.我会添加一列指示他们属于哪个组。 So, for example, in df_Allo_NHL
would have all of the observations have Allo NHL
for group
:因此,例如,在df_Allo_NHL
,所有观察结果都具有Allo NHL
for group
:
df_Allo_NHL <- data.frame(group = "Allo NHL",
time = c(28,32,49,84,357,933,1078,1183,1560,2114,2144),
censor = c(rep(1,5), rep(0,6)))
Or just adding to the 2 vectors you have already:或者只是添加到您已经拥有的 2 个向量中:
df_Allo_NHL <- data.frame(group = "Allo NHL", time = time_Allo_NHL, censor = censor_Allo_NHL)
Then once you have your 4 data frames, you can combine them.然后,一旦您拥有 4 个数据框,就可以将它们组合起来。 One way to do this is by using Reduce
and putting all your data frames in a list.一种方法是使用Reduce
并将所有数据框放在一个列表中。 The final result should be ready for cox proportional hazards analysis, in long form, and you will have group
available to include.最终结果应该准备好用于 cox 比例风险分析,以长形式显示,并且您将有可用的group
来包括。 (Edit: Z1 and Z2 added from table for model.) (编辑:Z1 和 Z2 从模型表中添加。)
time_Allo_NHL<- c(28,32,49,84,357,933,1078,1183,1560,2114,2144)
censor_Allo_NHL<- c(rep(1,5), rep(0,6))
df_Allo_NHL <- data.frame(group = "Allo NHL",
time = time_Allo_NHL,
censor = censor_Allo_NHL,
Z1 = c(90,30,40,60,70,90,100,90,80,80,90),
Z2 = c(24,7,8,10,42,9,16,16,20,27,5))
time_Auto_NHL<- c(42,53,57,63,81,140,176,210,252,476,524,1037)
censor_Auto_NHL<- c(rep(1,7), rep(0,1), rep(1,1), rep(0,1), rep(1,1), rep(0,1))
df_Auto_NHL <- data.frame(group = "Auto NHL",
time = time_Auto_NHL,
censor = censor_Auto_NHL,
Z1 = c(80,90,30,60,50,100,80,90,90,90,90,90),
Z2 = c(19,17,9,13,12,11,38,16,21,24,39,84))
time_Allo_HOD<- c(2,4,72,77,79)
censor_Allo_HOD<- c(rep(1,5))
df_Allo_HOD <- data.frame(group = "Allo HOD",
time = time_Allo_HOD,
censor = censor_Allo_HOD,
Z1 = c(20,50,80,60,70),
Z2 = c(34,28,59,102,71))
time_Auto_HOD<- c(30,36,41,52,62,108,132,180,307,406,446,484,748,1290,1345)
censor_Auto_HOD<- c(rep(1,7), rep(0,8))
df_Auto_HOD <- data.frame(group = "Auto HOD",
time = time_Auto_HOD,
censor = censor_Auto_HOD,
Z1 = c(90,80,70,60,90,70,60,100,100,100,100,90,90,90,80),
Z2 = c(73,61,34,18,40,65,17,61,24,48,52,84,171,20,98))
myData <- Reduce(rbind, list(df_Allo_NHL, df_Auto_NHL, df_Allo_HOD, df_Auto_HOD))
Edit编辑
If you go ahead and also add Z1
(Karnofsky Score) and Z2
(waiting time from diagnosis to transplant), you can do the CPH survival model like this below.如果您继续并添加Z1
(卡诺夫斯基评分)和Z2
(从诊断到移植的等待时间),您可以像下面这样创建 CPH 生存模型。 group
is already a factor and the first level Allo NHL
would by default be there reference category. group
已经是一个因素,默认情况下,第一级Allo NHL
将是参考类别。
library(survival)
Coxfit<-coxph(Surv(time,censor)~group+Z1+Z2, data = myData)
summary(Coxfit)
Output输出
Call:
coxph(formula = Surv(time, censor) ~ group + Z1 + Z2, data = myData)
n= 43, number of events= 26
coef exp(coef) se(coef) z Pr(>|z|)
groupAuto NHL 0.77357 2.16748 0.58631 1.319 0.18704
groupAllo HOD 2.73673 15.43639 0.94081 2.909 0.00363 **
groupAuto HOD 1.06293 2.89485 0.63494 1.674 0.09412 .
Z1 -0.05052 0.95074 0.01222 -4.135 3.55e-05 ***
Z2 -0.01660 0.98354 0.01002 -1.656 0.09769 .
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
exp(coef) exp(-coef) lower .95 upper .95
groupAuto NHL 2.1675 0.46136 0.6869 6.8395
groupAllo HOD 15.4364 0.06478 2.4419 97.5818
groupAuto HOD 2.8948 0.34544 0.8340 10.0481
Z1 0.9507 1.05181 0.9282 0.9738
Z2 0.9835 1.01674 0.9644 1.0030
Concordance= 0.783 (se = 0.059 )
Likelihood ratio test= 32.48 on 5 df, p=5e-06
Wald test = 28.48 on 5 df, p=3e-05
Score (logrank) test = 39.45 on 5 df, p=2e-07
Data数据
group time censor Z1 Z2
1 Allo NHL 28 1 90 24
2 Allo NHL 32 1 30 7
3 Allo NHL 49 1 40 8
4 Allo NHL 84 1 60 10
5 Allo NHL 357 1 70 42
6 Allo NHL 933 0 90 9
7 Allo NHL 1078 0 100 16
8 Allo NHL 1183 0 90 16
9 Allo NHL 1560 0 80 20
10 Allo NHL 2114 0 80 27
11 Allo NHL 2144 0 90 5
12 Auto NHL 42 1 80 19
13 Auto NHL 53 1 90 17
14 Auto NHL 57 1 30 9
15 Auto NHL 63 1 60 13
16 Auto NHL 81 1 50 12
17 Auto NHL 140 1 100 11
18 Auto NHL 176 1 80 38
19 Auto NHL 210 0 90 16
20 Auto NHL 252 1 90 21
21 Auto NHL 476 0 90 24
22 Auto NHL 524 1 90 39
23 Auto NHL 1037 0 90 84
24 Allo HOD 2 1 20 34
25 Allo HOD 4 1 50 28
26 Allo HOD 72 1 80 59
27 Allo HOD 77 1 60 102
28 Allo HOD 79 1 70 71
29 Auto HOD 30 1 90 73
30 Auto HOD 36 1 80 61
31 Auto HOD 41 1 70 34
32 Auto HOD 52 1 60 18
33 Auto HOD 62 1 90 40
34 Auto HOD 108 1 70 65
35 Auto HOD 132 1 60 17
36 Auto HOD 180 0 100 61
37 Auto HOD 307 0 100 24
38 Auto HOD 406 0 100 48
39 Auto HOD 446 0 100 52
40 Auto HOD 484 0 90 84
41 Auto HOD 748 0 90 171
42 Auto HOD 1290 0 90 20
43 Auto HOD 1345 0 80 98
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