使用对象内的对象对数组进行排序

Question

I have this array:

[
  ["name1", { count: 20 }],
  ["name2", { count: 10 }]
]

How would I go about sorting this array by the value of count?

I have tried using the sort function,

const sort = Array.sort((a, b) => b.count - a.count);

But this didn't change anything.

Answer 1

You need to access the second entry in the arrays inside the outer array. Your code is using count on the array entries, but they don't have a count property:

theArray.sort((a, b) => b[1].count - a[1].count);

Note also that you call sort on the actual array, not the Array constructor. It also sorts the array in-place, rather than returning a sorted array (it also returns the array you call it on, though).

Live Example:

 const theArray = [ ["name1", { count: 20 }], ["name2", { count: 10 }], ["name3", { count: 15 }] ]; console.log("before:", theArray); theArray.sort((a, b) => b[1].count - a[1].count); console.log("after:", theArray);

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