React java 脚本：IF 函数仅在单击按钮时起作用一次

Question

So I am using react native, and firebase db.

On register form button click i have function which creates user and also upload some info like city phone lalala:

   handleSignUp = () => {
    Fire.shared.createUser(this.state.email, this.state.password, this.state.name, this.state.avatar, this.state.mobile, this.state.pickerSelection, this.state.errorMessage)

    if (this.state.name == "") this.setState({ errorMessage: "Vartotojo vardas privalomas" });
        else  if (this.state.email == "") this.setState({ errorMessage: "El. pašto adresas privalomas" });
            else if (this.state.password == "") this.setState({ errorMessage: "Slaptažodis privalomas" });
                else  if (this.state.password2 == "") this.setState({ errorMessage: "Pakartokite slaptažodį" });
                    else  if (this.state.city == "") this.setState({ errorMessage: "Telefono nr. privalomas" });    
                        else  if (this.state.mobile == "") this.setState({ errorMessage: "Miestas privalomas" });    
                             else if ( this.state.password != this.state.password2) this.setState({ errorMessage: "Slaptažodžiai nesutampa" });
                                else { 
                                    Fire.shared.createUser(this.state.email, this.state.password, this.state.name, this.state.avatar, this.state.mobile, this.state.pickerSelection);
                                };
   };

So first time function works. any of these IFS. if I leave blank input I see error message nicely, but if I press button one more time it is just creating user anyway, even with empty values... like literaly this all works only once...

Here is my create user function:

   handleSignUp = () => {
    Fire.shared.createUser(this.state.email, this.state.password, this.state.name, this.state.avatar, this.state.mobile, this.state.pickerSelection, this.state.errorMessage)

    if (this.state.name == "") this.setState({ errorMessage: "Vartotojo vardas privalomas" });
        else  if (this.state.email == "") this.setState({ errorMessage: "El. pašto adresas privalomas" });
            else if (this.state.password == "") this.setState({ errorMessage: "Slaptažodis privalomas" });
                else  if (this.state.password2 == "") this.setState({ errorMessage: "Pakartokite slaptažodį" });
                    else  if (this.state.city == "") this.setState({ errorMessage: "Telefono nr. privalomas" });    
                        else  if (this.state.mobile == "") this.setState({ errorMessage: "Miestas privalomas" });    
                             else if ( this.state.password != this.state.password2) this.setState({ errorMessage: "Slaptažodžiai nesutampa" });
                                else { 
                                    Fire.shared.createUser(this.state.email, this.state.password, this.state.name, this.state.avatar, this.state.mobile, this.state.pickerSelection);
                                };
   };

Maybe it is because of ASYNC and AWAIT? Im using in only because of tutorial, im not sure what is that.

Answer 1

您调用 Fire.shared.createUser() 两次，第一次是在您的检查之前（因此无论如何它都会创建用户），第二次是您的检查通过时；