python flask URL 错误：'在服务器上找不到请求的 URL。 如果您手动输入了 URL，请检查您的拼写并重试。

Question

When I try to apply the url route I got this error. Here is the code:

from flask import Flask
from flask_restplus import Resource, Api

app = Flask(__name__)
api = Api(app)

@api.route('/GET/collections/<id>/<year>?q=<query>')
class DataRetrive(Resource):
    def get(self,id, year, query):
        return 'yes'

if __name__ == '__main__':
    app.run(debug=True)

Answer 1

I think you don't need specify the query parameter "q"

try something like this:

from flask import Flask, request
from flask_restplus import Resource, Api

app = Flask(__name__)
api = Api(app)

@api.route('/GET/collections/<id>/<year>')
class DataRetrive(Resource):
    def get(self,id, year):
        q = request.args.get('q')
        return 'yes'

if __name__ == '__main__':
    app.run(debug=True)

Pay attention to the country parameter that you have not defined ...

So your url looks like this:

localhost:5000/GET/collections/1/2020?q=something