如何在子列表中的字符串之间找到完全匹配

Question

I have two lists composed of sublists, something like:

 conopt = [["element1","element2"],["bla"]] 
 mat = [["element1","elementA"],["bla & etc"]] 

From that data I want to fill a matrix with dimensions len(conopt) x len(mat). Since python by default doesn't have a matrix I'll use another list with sublists:

finalmat = [ ["-","X",...,"X"],[...]]

I want finalmat to have an "X" where there is a full match (when a subelement of conopt matches a subelement of mat) and a "-" where there isn't. However I only care about the first full match for each sublist. If a sublist of conopt has 1 or more matches on a sublist of mat, the result should be the same, only one "X".

I've tried the following:

for i in mat:
    for j in conopt:
         for item in j:
             if item in i:
                 finalmat[mat.index(i)][conopt.index(j)] = "X"

However the result is not correct, because I've manually checked some data points and it doesn't give the correct result.

---

some extra (less important) info:

• the string elements are composed of letters, numbers, spaces (only spaces between words) and "#&" characters.

• the sublists have an arbitrary number of strings.

• this data comes from an excel file. I've manually extracted and modified it to match the python syntax.

• the output (finalmat) is going back to excel. I'm doing this step manually because this is an one off task and I don't want to complicate my code even more.

Answer 1

mat.index(i) and conopt.index(j) will not find i and j in sublists . I suggest using enumerate . Also make sure you correctly initialize finalmat .

finalmat = [ [ "-" for j in range(len(conopt) ] for i in range(len(mat)) ]
for indexmat, itemmat in enumerate(mat):
    for indexconopt, itemconopt in enumerate(conopt):
         for item in itemconopt:
             if item in itemmat:
                 finalmat[indexmat][indexconopt] = "X"