在没有 .get() 的情况下从结构返回成员

Question

Let's say I have following structure

template<typenameT>
class Foo
{
  T value;
  public:
    // some public logic
}

all what I want on this point is being able to say

Foo<int> A;

and then get value out of A as if it ware "just value of type T" and use it as follows

int val1 = A;  // must correspond to int val1 = A.value
               // and
int& val2 = A; // must return reference of A.value and so on

I really don't want to user set/get because I am going to write such calls very often and want therefor simplify the code as much as possible.

Firstly I thought overloading = might help, but I didn't get it right. It works for the opposite with the assignment operator such as Foo<int> A; int val = 1; A = val; Foo<int> A; int val = 1; A = val;

EDIT: There is sure already answer on the web, but I couldn't find it under "assignment" keyword.

Answer 1

it seems you want to overload user-defined conversion operators:

template <typename T>
class Foo
{
  T value;
public:
    operator T () const { return value; }
    operator T& () { return value; }

    // some public logic
};