将带有字典的字典转换为具有相同键值对的列表

Question

I have dictionary and within that dictionary contains many dictionaries

for example

Dict_a = {'Dict1': {'name': 'Ali', 'age': 19},

        'Dict2': {'name': 'Bob', 'age': 21},

        'Dict2': {'name': 'Ali', 'age': 21}}

now I want to convert these dictionary into this dictionaries with common key values go into one list

Dict_b = {"distinct": [], "match": [[{'name': 'Ali', 'age': 19},

        {'name': 'Ali', 'age': 21}],

        [{'name': 'Bob', 'age': 21}]] }

is there any efficient way to do this?

Answer 1

Try this one:

payload = {}

for dict_name, value in Dict_a.items():
    if value["name"] in payload.keys():
        payload[value["name"]].append(value)
    else:
        payload[value["name"]] = [value]

Dict_b = {"distinct": [], "match": payload.values()}