尽管包含不存在的电子邮件，Python sendmail() 仍返回 {}

Question

I was experimenting sending emails using python and smtplib . I am aware that if the email was sent to all email addresses then sendmail() returns {}. But I intentionally added 2 email addresses (bbbbbbbbbb@gmail.com and ccccccccccccc@gmail.com) that do not exist (I confirmed they don't exist by checking sent items in my gmail account) and still got an empty dictionary. Is something going wrong here?

import smtplib

smtpobj=smtplib.SMTP('smtp.gmail.com',587) #creating an SMTP object. 
smtpobj.ehlo() #saying hello to the server

smtpobj.starttls() #enabling encryption for the connection

password=str(input("Please enter your password: "))

smtpobj.login('thereallasad@gmail.com', password) #logging in to account

lst=['govindsomadas@gmail.com', 'thereallasad@gmail.com', 'bbbbbbbbbbbbbbbbbb@gmail.com','ccccccccccccccccc@gmail.com']

smtpobj.sendmail('thereallasad@gmail.com', lst, 'Subject: Testing\nDear Govind,\n\nThanks for creating me.\n\nRegards,\nLasad')

print(smtpobj.sendmail('thereallasad@gmail.com', lst, 'Subject: Testing\nDear Govind,\n\nThanks for creating me.\n\nRegards,\nLasad'))

smtpobj.quit() #disconnects from smtp server

Answer 1

It will return an empty dictionary if even one of the email addresses worked, if none works then it raises an exception. Try sending an email to all the wrong emails.