[英]Get for each row of list-column the length
Problem: I want to find out the number of elements in a list-column (here y
).问题:我想找出列表列中的元素数(这里是
y
)。 Is there a more efficient and elegant way to determine this rather with purrr::map
-function?有没有更有效和优雅的方法来确定这一点,而不是使用
purrr::map
? This is really slow when trying to apply this to a data.table object with more than 700,000 rows.尝试将其应用于具有超过 700,000 行的 data.table 对象时,这真的很慢。
library(data.table)
dt <- data.table(
x = seq(4),
y = list(c(1, 2, 3), c(2, 3), c(5, 1), c(12, 90, 200))
)
dt[, class(y)]
## more efficient/elegant way?
dt[, purrr::map(y, length)]
You can do:你可以做:
dt[, lengths(y)]
[1] 3 2 2 3
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