[英]How to convert CURL command with python requests and retrieve results via API
I'm new to python and encountered problems passing the parameters below that I want to request from the server via API.我是 python 的新手,在传递下面我想通过 API 从服务器请求的参数时遇到了问题。
I'm using flask as I want this to be web based.我正在使用烧瓶,因为我希望它是基于网络的。 Step1: go to index.html and pass teamID
teamID = request.form['teamID']
.步骤 1:转到 index.html 并传递 teamID
teamID = request.form['teamID']
。 Step2: Authenticate user via API & find data by teamID Step3: Go to the page report.html and display results + save results as CSV file步骤2:通过API验证用户并通过teamID查找数据步骤3:转到页面report.html并显示结果+将结果保存为CSV文件
import subprocess
import json
import requests
from flask import Flask, render_template, request
#required parameters
myID = 12345
teamID = 3456
includeSub = 0
beginDate = "2020-03-20 00:00:00"
endDate = "2020-03-22 00:00:00"
Type = 1
authToken = "1245dgfdfg655432gf"
serverURL = https://myurl.com/env/re/
#optional parameters
Category = 1
fpDate = 1
versionP = "1.0"
-----------------
This is CURL command that I would like to convert into python requests format:这是我想转换为 python 请求格式的 CURL 命令:
#Curl command that i need to covert to python requests format
"curl -X POST -H \"Content-Type: application/json\" -H \"accessToken:" & authToken & "\" \"" & serverURL & "teamID/" & teamID & "/report\" -d $'" & commandBody & "'"
my code so far:到目前为止我的代码:
app = Flask(__name__)
@app.route('/reports', methods=['POST'])
def getmyTeamReport(authToken, myID):
teamID = request.form['teamID']
headers = { 'accept': 'application/json',
'Content-Type': 'application/json',
'accessToken': authToken,
'userID': myID}
commandBody = {
"teamID": teamID,
"includeSub": includeSub,
"beginDate": beginDate,
"endDate": endDate,
"Category": Category,
"fpDate": fpDate,
"versionP": versionP
}
endpoint ='/report'
r = requests.get(serverURL+teamID+endpoint+headers=headers+commandBody=commandBody)
json_object = r.json()
report_t = json_object
return render_template('report.html', report=report_t)
@app.route('/')
def index():
return render_template('index.html')
if __name__ == '__main__':
app.run(debug=True)
Could someone help with this?有人可以帮忙吗? So far I tried the code above but received
SyntaxError: invalid syntax
or TabError: inconsistent use of tabs and spaces in indentation
到目前为止,我尝试了上面的代码,但收到
SyntaxError: invalid syntax
或TabError: inconsistent use of tabs and spaces in indentation
Thanks in advance!提前致谢!
Thanks to TrillWorks , we have now an online curl to python converter.感谢TrillWorks ,我们现在有了一个在线 curl 到 python 转换器。
So for:因此对于:
curl -X POST -H \"Content-Type: application/json\" -H \"accessToken:" & authToken & "\" \"" & serverURL & "teamID/" & teamID & "/report\" -d $'" & commandBody & "'
You have:你有:
import requests
headers = {
'\\Content-Type': 'application/json" -H "accessToken:',
}
response = requests.post('http://&', headers=headers)
To avoid TabError
:为了避免
TabError
:
app = Flask(__name__)
@app.route('/reports', methods=['POST'])
def getmyTeamReport(authToken, myID):
teamID = request.form['teamID']
headers = { 'accept': 'application/json', 'Content-Type': 'application/json','accessToken': authToken,'userID': myID}
commandBody = {"teamID": teamID,"includeSub": includeSub,"beginDate": beginDate,"endDate": endDate,"Category": Category,"fpDate": fpDate,"versionP": versionP}
endpoint ='/report'
r = requests.get(serverURL+teamID+endpoint+headers=headers+commandBody=commandBody)
json_object = r.json()
report_t = json_object
return render_template('report.html', report=report_t)
@app.route('/')
def index():
return render_template('index.html')
if __name__ == '__main__':
app.run(debug=True)
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