Kivy 返回 AttributeError：对象在明确拥有时没有属性“名称”

Question

I'm trying to build an interactive school timetable using Kivy but I keep running into problems with changing the Button text based on its name. I have created a grid layout where each button has a unique name, for example the first Button in Monday is one_mon the next one is two_mon and so on. I have created a class which inherits from Button and here is the Kivy and Python code for this class:

<Tile>:
    background_color: [.5, .9, 1, 1]
    halign: "center"
    size_hint: None, None
    size: 96, 96
    text: self.lesson
    on_press: self.on_press()
    on_release: self.on_release()

Here is the Python code for Tile

class Tile(Button):
    def __init__(self, **kwargs):
        super().__init__(**kwargs)
        self.lesson = ""
        self.sub_press = ""
        self.check()
        self.text = self.lesson

    def check(self):
        if self.name == "one_mon":
            self.text = "English"
            self.sub_press = "Room nr. 42 \n Mr. Hetman"

        ...        

        else:
            self.lesson = "None"
            self.sub_press = "None"

    def on_release(self):
        self.text = self.lesson
        self.background_color = [.5, .9, 1, 1]

    def on_press(self):
        self.text = self.sub_press
        self.background_color = [.01, .9, 1, 1]

Using print(self.name) under on_press function of Tile class works fine and returns the name of the button but using if self.name == "one_mon" raises an AttributeError 'Tile' object has no attribute 'name'

Here is the code for the parent widget holding all those buttons together:

<PlanChart>:
    cols: 11
    padding: 2
    Tile:
        id: one_mon
        name: "one_mon"
    Tile:
        id: two_mon
        name: "two_mon"
    Tile:
        id: three_mon
        name: "three_mon"

    ......

    Tile:
        id: ten_fri
        name: "ten_fri"

How can I assign a different text to a button based on its id or its name? I can't just assign the text to each button individualy becouse in the future I want to be able to switch beetwen diffrent students whose timetable might look diffrent.

Answer 1

When you do self.name , it would search for a variable name within the class (which is not declared)

In order to access the id from the kv code, you need to do the following

if self.ids.one_mon.name == "one_mon"

hope it helps