如果列表中有任何偶数，如何检查python

Question

I am a newbie who just start learning python. here is my list:

list1 = [3,105,97,17,68241,5,3,8,]

how I will check if there is any even number in my list

Answer 1

Try and identify what makes a number even. In your head, what could you do to the number to prove it is even? You divide it by 2 and see if the remainder is 0. In programming, we use the modulo operator (%) to get the remainder of an equation.

Try and think of a way that you can iterate over the items in your list and see if they are even using the above method.

Answer 2

You can use the Python builtin function which name is any(). here is my code which will check if your list have any even number. You will get true value if there is any even number in your list otherwise it will return false.

list1 = [3,105,97,17,68241,5,3,8,]
print(any(num%2 == 0 for num in list1))