我的 C 程序中的 function 出现问题。 程序在执行“encript()”function 中的倒数第二个“printf()”之前终止

Question

When I call "encript()", it works how I want it to until the second last "printf()" at which point the program terminates without executing any more lines. I tried searching for similar questions here and tried to fix my code but nothing that I could find seemed to work. I am a beginner so please forgive me if it's just a simple mistake.

char encript(int x){
    printf("You selected Encription with the key: %d\n\n", x);  //Tells user the key value they input
    Sleep(1000);
    int msglength = 100;  //Variable for the amount of characters in the messge
    printf("\n\nEnter aproximate number of characters in you message. \nThe number must be at least 1 over the amount of characters in your message: ");
    scanf("%d", msglength);    //assigns user input integer to msglength
    printf("\n\n");
    char message[msglength];    //Creates a character array for the message with a length of "msglength"
    printf("Insert message here: ");    ////THIS LINE DOES NOT SEEM TO EXECUTE. NOR DO THE TWO BELOW IT.
    scanf("%s", message);
    printf("\n\n%s", message);
}

Thanks!

Answer 1

pay attention to this line scanf("%d", msglength); , for scanning variables you should send their address to scnaf , so this should be scanf("%d", &msglength); (add & to scanf )

this function should return a character,if you just want to to scan a message and print it, you should use void like this void encript(int x) also if you want to return message you can use char * encript(int x) .