Python 3.x — 根据另一个列表对一个列表进行排序，然后返回已排序的两个列表

Question

Problem: I would like to sort one list based on another list and then return both lists sorted.

I'm doing it like this:

points = [4,7,3,2,7]
candidates = ['a', 'b', 'c', 'd', 'e']

ordered_candidates = [x for _, x in sorted(zip(points, candidates), reverse=True)]
ordered_points = sorted(points, reverse=True)

Question : Is it possible to merge the last two lines into one line?

I found question: Sorting list based on values from another list? but it's not exactly what I'm asking for.

Answer 1

Is it possible to merge the last two lines into one line?

Yes it is. ordered_candidates excludes the points from the result, since you only choose the candidates with [x for _, x in...] . This basically only selects the second item from each tuple. Additionally, ordered_points sorts only the points. They both also sort in reverse with reverse=True .

Seems like you can just modify ordered_candidates to include both items in the (point, candidate) pairs.

>>> points = [4,7,3,2,7]
>>> candidates = ['a', 'b', 'c', 'd', 'e']
>>> sorted(zip(points, candidates), reverse=True)
[(7, 'e'), (7, 'b'), (4, 'a'), (3, 'c'), (2, 'd')]

Answer 2

It is possible to do this by:

• changing, slightly, what save in the inner list comprehension
• unpacking that list comprehension
• zipping that unpacked data, which stores the results into two tuples the same length as the original inputs, but with the appropriate sorting preserved
• unpacking the results into two variables on a single line

points = [4,7,3,2,7]
candidates = ['a', 'b', 'c', 'd', 'e']

ordered_candidates, ordered_points = zip(*[(p, c) for p, c in sorted(zip(points, candidates), reverse=True)])```