如果 list = x 的任何值，请执行此操作

Question

cat = [1, 2, 3]


def any_of_list(LIST):

    if ***any value of LIST*** == 2:

        print('yes')

    else:

        print('no')



any_of_list(cat)

OUTPUT = 'yes'

Im not sure how to enter the bold. Please help.

Answer 1

The general case would be to use built-in any like

def any_of_list(LIST):
    if any(x == 2 for x in LIST):
        print('yes')
    ...

Another example if any(i % 3 == 0 for i in LIST): to find if there is a multiple of 3 in the list

---

But here as you just look for inclusion you can do

def any_of_list(LIST):
    if 2 in LIST:
        print('yes')
    ...

Answer 2

Try

if any(x == 2 for x in LIST):

Answer 3

If you want to solve that explicitly, do

def any_of_list(l):
    for x in l:
        if x == 2:
            return True
    return False

If you want to use the functional programming features of Python, on the other hand,

def any_of_list(l):
    return any(map(lambda x: x == 2, l))

will do the same. If you want to use this approach, make sure to look up any , map and lambda in the Python Library and Language Reference.

Beware that any_of_list is a rather bad name for that function, it is not very descriptive. Go for something like any_is_two .