Azure - 基于 YAML 的管道中的自定义条件

Question

I've an yaml based azure CI/CT pipeline. I've a task defined as below:

- task: PublishTestResults@2
  displayName: 'Publish PCOM Test Results'
  condition: always()
  inputs:
    testResultsFormat: NUnit
    testResultsFiles: '*.xml'
    searchFolder: '$(Common.TestResultsDirectory)/$(Build.SourceBranchName)/$(Build.BuildNumber)/test-results/PCOM'
    mergeTestResults: true
    testRunTitle: 'PCOM Tests'

It looks for all '*.xml' files under a particular s3 location. But the xml files will be created only if the below task is successful:

- bash: 'perl run_aws_cli.pl $(Build.BuildNumber) $(Build.SourceBranchName) $(s3Bucket) $(Build.SourcesDirectory)'
  workingDirectory: 'azure-pipeline/scripts'
  displayName: 'Run ECS Tasks'

So I want a custom condition to check if the later task is successful then only search xml files in the directory else don't search for it. Currently it's searching always and the earlier task( Publish PCOM Test Results ) is failing.

Answer 1

just do condition: succeeded() on your second task. this will only run if all the tasks before that run successfully. if you want a more sophisticated option, check this thread.

Alternatively, you can probably get more information on the build status from the API.

https://docs.microsoft.com/en-us/rest/api/azure/devops/build/builds/get?view=azure-devops-rest-5.1