从文本文件中查找内容与某行匹配的文件

Question

I have a text file - accessions.txt (below is a subset of this file):

KRO94967.1
KRO95967.1
KRO96427.1
KRO94221.1
KRO94121.1
KRO94145.1
WP_088442850.1
WP_088252850.1
WP_088643726.1
WP_088739685.1
WP_088283155.1
WP_088939404.1

And I have a directory with multiple files ( *.align ).

I want to find the filenames ( *.align ) which content matches any line within my accessions.txt text file.

I know that find. -exec grep -H 'STRING' {} + find. -exec grep -H 'STRING' {} + works to find specific strings (eg replacing STRING with WP_088939404.1 returns every filename where the string WP_088939404.1 is present).

Is there a way to replace STRING with "all strings inside my text file"?

Or

Is there another (better) way to do this?

I was trying to avoid writing a loop that reads the content of all my files as there are too many of them.

Many thanks!

Answer 1

grep can take a list of patterns to match with -f .

grep -lFf accessions.txt directory/*.align

-F tells grep to interpret the lines as fixed strings, not regex patterns.

Sometimes, -w is also needed to prevent matching inside words, eg

abcd

might match not only abcd , but also xabcd or abcdy . Sometimes, preprocessing the input list is needed to prevent unwanted matching if the rules are more complex.

Answer 2

You're looking for grep's -f option.

find . -name '*.align' -exec grep -Fxqf accessions.txt {} \; -print