使用 Laravel 从数据库中获取最新和不同的值

Question

new to the community, would like to say thankyou to all the contributers!

Right now i'm needing a solution to get the Latest & Distinct value from a table.

The table I have is called ' transactions ' which has 'id', 'value', 'remarks', 'memberId(FK)', 'created_at' .

ID | amount |  memberId | created_at
 1 |  101   |  00001    | 22-04-2018
 2 |  102   |  00002    | 22-04-2018
 3 |  103   |  00002    | 22-04-2018
 4 |  104   |  00001    | 24-04-2018 (latest)
 5 |  105   |  00002    | 25-04-2018 (latest)
 6 |  106   |  00003    | 25-04-2018 (latest)

my expected result is

ID | amount |  memberId | created_at
 4 |  104   |  00001    | 24-04-2018
 5 |  105   |  00002    | 25-04-2018
 6 |  106   |  00003    | 25-04-2018

My code

      $transactions = Transaction::select('id', 'memberId', 'amount', DB::raw('max(created_at) as latest_depo'), 'created_at', 'amount')
   ->groupBy('memberId')
   ->orderBy('latest_depo' , 'desc')
   ->paginate(50);

but I end up not getting the Latest Row of each member. My guess is something to do with the grouping of the values. Thanks in advance!

Answer 1

How about:

$transactions = Transaction::latest()
    ->groupBy('memberId')
    ->distinct('memberId')
    ->select('id','amount','memberId','created_at')
    ->paginate(50);

Edit: I added groupBy() to the above query. If groupBy() gives you an error, verify your database configuration as described here .

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Note: If you are using Laravel Eloquent relationships, your memberId column should probably named member_id .