如何替换不在两个字符之间的所有字符串？

Question

Example (replacing 'text' with '...'):

Before: text(text)text

After: ...(text)...

Answer 1

In this case it is easier to find what you want to keep, and replace the rest.

Eg like this:

static String abbreviate(String input, String openTag, String closeTag) {
    String regex = Pattern.quote(openTag) + ".*?" + Pattern.quote(closeTag);
    StringBuilder buf = new StringBuilder();
    int start = 0;
    for (Matcher m = Pattern.compile(regex).matcher(input); m.find(); start = m.end()) {
        if (start < m.start())
            buf.append("...");
        buf.append(m.group());
    }
    if (start < input.length())
        buf.append("...");
    return buf.toString();
}

Test

System.out.println(abbreviate("text(text)text(text)text", "(", ")"));
System.out.println(abbreviate("text$text$text$text$text$text", "$", "$"));
System.out.println(abbreviate("text(text)text", ")", "("));

Output

...(text)...(text)...
...$text$...$text$...
...

Answer 2

You need to iterate over the characters and only append those that are between the two specified characters. This can be done as follows:

private String splitStr(String str, char first, char second) {
        StringBuilder sb = new StringBuilder();
        if(str.isEmpty() || str.indexOf(first) < 0 || str.indexOf(second) < 0)
            return sb.toString();
        char[] chars = str.toCharArray();
        boolean append = false;
        for(char c : chars) {
            if(c == first) {
                sb.append(c);
                append = true;
            }else if(c == second) {
                sb.append(c);
                append = false;
            }else if(append)
                sb.append(c);
        }
        return sb.toString();
}

Some sample cases are:

"text(text)text(text)text(text)text" => "(text)(text)(text)"

"text(text)text" => "(text)"

Answer 3

String s = "text(text)text";
String newString = s.replace("text", "...");
System.out.println(newString);      //returns ...(...)...

1. Note that "(text)" still contains "text", the braces around it will not stop it from being replaced.

2. You need to assign the result to a new String to use it. Strings are immutable