[英]Struct inside a struct call in C
I got this struct and I want to call it by a good way !我得到了这个结构,我想用一个好方法来调用它!
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
};
I made this code for the call of my struct:我为调用我的结构制作了这段代码:
struct TreeNode left2 = {
4
};
struct TreeNode right2 = {
5
};
struct TreeNode left = {
2,
&left2,
&right2
};
struct TreeNode right = {
3
};
struct TreeNode binary = {
1,
&left,
&right
};
But that's a little bit loud, is there another way (without changing the struct), simplest, to do it?但这有点响亮,有没有另一种方法(不改变结构),最简单的方法?
You can put all the nodes into a single array (I put the root node into index#0):您可以将所有节点放入一个数组中(我将根节点放入 index#0):
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
};
struct TreeNode all[] = {
{ 1, &all[1], &all[2]}, // Binary(root)
{ 2, &all[3], &all[4]}, // Left
{ 3, NULL, NULL}, // Right
{ 4, NULL, NULL}, // Left2
{ 5, NULL, NULL}, // Right2
};
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.