Powershell 在条件下导入 csv 文件的前两列中的值

Question

I have the following code which is importing csv data and exporting into an excel spreadsheet.
How do I export-excel, just the "Name" column values (first column), if the 'Status' column value (second column) is equal to "Active"?

Import-Csv -Path 'C:\Data\mergeSessions\CiscoAnyconnect.csv' | Sort-Object -Property 'Name' -Unique | Export-Excel -Path 'C:\Data\mergeSessions\reports\reportVCX01.xlsx' -WorkSheetname 'vpn'

And for the below code, how to I export-excel, just the value from the 'Associated User' column (first column)?

Import-Csv C:\Data\mergeSessions\SessionSummary.csv | Sort-Object 'Associated User' -Unique | Export-Excel -Path C:\Data\mergeSessions\reports\reportVCX01.xlsx -WorksheetName 'citrix'

Answer 1

For the first part of the question you could do:

Import-Csv -Path 'C:\Data\mergeSessions\CiscoAnyconnect.csv' |
Where-Object { $_.Status -eq 'Active' } |
Select-Object Name -Unique | Sort-Object |
Export-Excel -Path 'C:\Data\mergeSessions\reports\reportVCX01.xlsx' -WorkSheetname 'vpn'

The second part is easier because there is no condition:

Import-Csv -Path 'C:\Data\mergeSessions\SessionSummary.csv' |
Select-Object 'Associated User' -Unique | Sort-Object |
Export-Excel -Path 'C:\Data\mergeSessions\reports\reportVCX01.xlsx' -WorksheetName 'citrix'