[英]how to create a multidimensional array on the fly using python?
I have a loop which generates a value_list each time it runs, at the end of each iteration i want to append all the lists into a one multi dimensional array我有一个循环,每次运行时都会生成一个 value_list,在每次迭代结束时,我想 append 将所有列表放入一个多维数组中
I have:我有:
value_list = [1,2,3,4]
in 1st iterationvalue_list = [1,2,3,4]
value_list = [5,6,7,8]
in 2nd iteration value_list = [5,6,7,8]
在第二次迭代中value list = [9,10,11,12]
in 3rd iterationvalue list = [9,10,11,12]
At the end of each iteration I want one multi dimensional array like在每次迭代结束时,我想要一个多维数组,例如
value_list_copy = [[1,2,3,4]]
in the 1st iteration value_list_copy = [[1,2,3,4]]
在第一次迭代中value_list_copy = [[1,2,3,4],[5,6,7,8]]
in the 2nd iteration value_list_copy = [[1,2,3,4],[5,6,7,8]]
在第二次迭代value_list_copy = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]
How could I achieve this?我怎么能做到这一点?
Thanks谢谢
You can use a nested comprehension and itertools.count
:您可以使用嵌套理解和
itertools.count
:
from itertools import count, islice
cols = 4
rows = 5
c = count(1)
matrix = [[next(c) for _ in range(cols)] for _ in range(rows)]
# [[1, 2, 3, 4],
# [5, 6, 7, 8],
# [9, 10, 11, 12],
# [13, 14, 15, 16],
# [17, 18, 19, 20]]
The cool kids might also want to zip
the count iterator with itself:酷孩子可能还想
zip
本身的计数迭代器:
list(islice(zip(*[c]*cols), rows))
# [(1, 2, 3, 4),
# (5, 6, 7, 8),
# (9, 10, 11, 12),
# (13, 14, 15, 16),
# (17, 18, 19, 20)]
If you are using Python3.8 then use Walrus assignment
( :=
).如果您使用的是Python3.8 ,则使用
Walrus assignment
( :=
)。
For Syntax and semantic
.对于
Syntax and semantic
。
count=0
rows=5
cols=4
[[(count:=count+1) for _ in range(cols)] for _ in range(rows)]
Output: Output:
[[1, 2, 3, 4],
[5, 6, 7, 8],
[9, 10, 11, 12],
[13, 14, 15, 16],
[17, 18, 19, 20]]
Without using :=
.不使用
:=
。
rows=5
cols=4
[list(range(i,i+cols)) for i in range(1,rows*cols,cols)]
Try this:尝试这个:
limit = 10
length_of_elements_in_each_list = 4
[range(i, i+length_of_elements_in_each_list) for i in range(1, limit)]
You can set a limit and length_of_elements_in_each_list according to your need.您可以根据需要设置限制和 length_of_elements_in_each_list。
Try this below:在下面试试这个:
value_list_copy = []
for i in range(n): # ----------> Assuming n is the number of times your loop is running
value_list_copy.append(value_list) # ------ Append your value list in value_list_copy in every iteration
Here you will get an array of arrays.在这里,您将获得一个 arrays 数组。
print(value_list_copy)
Here are two other possible solutions:以下是另外两种可能的解决方案:
Double for loop approach双循环方法
rows, cols, start = 3, 4, 1
value_list_copy = []
for j in range(rows):
value_list = []
for i in range(start, cols + start):
value_list.append((j*cols)+i)
value_list_copy.append(value_list)
print(
f'value_list = {value_list}\n'
f'value_list_copy = {value_list_copy}\n'
)
List comp method列表比较方法
rows, cols, start = 3, 4, 1
value_list_copy_2 = [
[
(j*cols)+i for i in range(start, cols + start)
] for j in range(rows)
]
print(f'value_list_copy_2 = {value_list_copy_2}')
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