FileNotFoundError：[Errno 2] Python 3.7 上的图片没有此类文件或目录

Question

I am a beginner on Python. I try to open a picture to print its size and format. My picture is in several folders:

• my images
• the folder of my Python codes
• the folder of anaconda3\lib\site-packages\PIL

I have already wrote only the name of the picture, then the exact path but nothing works (my picture is in .jpg ).

Here is my code:

from PIL import Image

image = Image.open("v")    
print("nbr of columns and lines", image.size, image.format)
data = list(image.getdata())
print(data[:30]) 

and my error message:

runfile('C:/Users/Optimal Conseil/.spyder-py3/temp.py', wdir='C:/Users/Optimal Conseil/.spyder-py3') Traceback (most recent call last):

File "C:\Users\Optimal Conseil.spyder-py3\temp.py", line 4, in image=Image.open("v")

File "C:\Users\Optimal Conseil\anaconda3\lib\site-packages\PIL\Image.py", line 2809, in open fp = builtins.open(filename, "rb")

FileNotFoundError: [Errno 2] No such file or directory: 'v'

Answer 1

If the image file "v" is in the same folder as your python code, your code should load it. The error shows it is missing the file. I would recommend checking for file extensions (maybe file name is "v.jpg").
And if your file is not in the python folder and is in a different folder, the easiest way is to include the full address to your image file:

image=Image.open("full_path_to_file/"+"v")

The same approach with better practice would be like this:

import os
image=Image.open(os.path.join("full_path_to_file", "v"))

You can also use the relational address to file. "../" will take you to one directory above your current directory. For example, if your file directory structure is:

• directory
  • |
  • v.jpg
  • subdirectory
    • |
    • your_python_code.py

You can use:

image=Image.open("../v")