在 arrays 的另一个数组中搜索一个数组的元素

Question

I have this two array: linesToWin and mosseX: []. A possible configuration of mosseX is: mosseX[1,3,4,7]. I want to control if there are three number in mosseX that are equal to an array of linesToWin and return true or false dipending by the searching. Someone could help me?

calculateWinner = () => {
  const linesToWin = [
    [0, 1, 2],
    [3, 4, 5],
    [6, 7, 8],
    [0, 3, 6],
    [1, 4, 7],
    [2, 5, 8],
    [0, 4, 8],
    [2, 4, 6],
  ];

  let result = false;
  for (let i = 0; i < linesToWin.length; i++) {
    result = this.state.mosseX.filter((mossa) =>
      mossa.includes(linesToWin[i].map((u) => u))
    );
    if (result === true) return result;
  }
  return result;
};

Answer 1

You can simply contact array and compare.

Sample:

calculateWinner = () => {
  const linesToWin = [
    [0, 1, 2],
    [3, 4, 5],
    [6, 7, 8],
    [0, 3, 6],
    [1, 4, 7],
    [2, 5, 8],
    [0, 4, 8],
    [2, 4, 6],
  ];
  function merge(data = []) {
    return data.join("-");
  }
  const mosseX = merge(this.state.mosseX);
  return linesToWin.some((line) => merge(line) === mosseX);
};

For testing:

 calculateWinner = (mosseX) => { const linesToWin = [ [0, 1, 2], [3, 4, 5], [6, 7, 8], [0, 3, 6], [1, 4, 7], [2, 5, 8], [0, 4, 8], [2, 4, 6], ]; function merge(data = []) { return data.join("-"); } // For testing // const mosseX = merge(this.state.mosseX); mosseX = merge(mosseX); return linesToWin.some((line) => merge(line) === mosseX); }; console.log(calculateWinner([6,7,1])) console.log(calculateWinner([6,7,8])) console.log(calculateWinner([1,7,8]))