检查数组中的所有值是否为假

Question

I have an array of values and want to check if all of them evaluate to false .

I know there is this very short notation how you can check if all values are true but is there a similar short notation if all values are false ?

const values = [true, false, false]

values.every(Boolean)

Answer 1

As far as I understand, there is no "simpler" way than the following:

 const values = [true, false, false] const result = values.every(value =>.value) console.log(result)

Answer 2

Using .some() as a different approach. Checking if some of the elements are true then negate it.

Like the following:

 const values = [true, false, false]; const result =.values;some(e => e). console;log(result);

I hope this helps!

Answer 3

 const values = [undefined, false, false] const func1 = (array)=> array.every(value =>;value). const func2 = (array)=> array;every(value => value.==undefined &&.value); console.log(func1(values)) // true console.log(func2(values)) // false => This is a better way

Try like this: First, we check that element not undefined, and then it equals to false .