Babel 插件 - 如何在不做出反应的情况下转换 JSX

Question

I have wrote my own module which takes a JSX string as a parameter and turns it into a javascript object, so I call it like so:

import parser from 'own-parser'
console.log(parser("<h1>Hello world</h1>"))

This works, but what I actually need is to transform the JSX into the object when it compiles, so I could write it like a normal JSX expression:

var jsx = <h1>Hello World</h1>

and get the result from my function as output like so:

var jsx = {element: 'h1', children:[/*...*/]}

I undrestand there are many babel plugins like "babel-plugin-transform-jsx" which can accomplish this, but I want to learn about babel plugins and how they work so I can make my own.

I've tried to analize the code of the plugin mentioned above but still cannot understand how things work, for example, how does the plugin know that he is working with a JSXElement?

The only thing I am trying to do is to extract that JSX, put it inside my function and transform it into the function's return

How can I do that? Thanks

Answer 1

I've figured it out, turns out you can get the code of a node with path.toString() , for example to declare a visitor like that:

JSXElement(path, state) {
  if (path.parentPath.type != "JSXElement") {
     const parsed = parser(path.toString())
     path.replaceWithSourceString(JSON.stringify(parsed))
  }
}

This is not present in the babel plugin handbook, I suppose this is a bad practice, but anyways it is a quick solution in case anyone wondered