[英]Check if the first element of scanner in Java
I have a txt file and there are separate values like 1 2 3 10 15 2 5... and I assign them to an arraylist as shown below.我有一个 txt 文件,并且有单独的值,例如 1 2 3 10 15 2 5...,我将它们分配给 arraylist,如下所示。 During this I need to omit the first value and I need to detect if the scanned value is the first value.
在此期间,我需要省略第一个值,并且需要检测扫描的值是否是第一个值。 I have tried something like indexOf, etc but not manage to fix.
我尝试过诸如 indexOf 之类的东西,但无法修复。 How can I detect the first element and use if()?
如何检测第一个元素并使用 if()?
private static ArrayList<Integer> convert() throws FileNotFoundException {
Scanner s = new Scanner(new File("C:\\list.txt"));
ArrayList<Integer> list = new ArrayList<Integer>();
while (s.hasNext()) {
int next = Integer.parseInt(s.next());
if (// s.next() is the first element of list.txt) {
}
list.add(next);
}
s.close();
return list;
}
Just use a counter to determine if it is the first element.只需使用计数器来确定它是否是第一个元素。
private static ArrayList<Integer> convert() throws FileNotFoundException {
Scanner s = new Scanner(new File("C:\\list.txt"));
ArrayList<Integer> list = new ArrayList<Integer>();
int i = 0;
while (s.hasNext()) {
int next = Integer.parseInt(s.next());
if (i == 0) {
//must be first element
} else {
// other elements
}
i++;
list.add(next);
}
s.close();
return list;
}
You can also use Scanner.nextInt()
and Scanner.hasNextInt()
and avoid having to parse it.您还可以使用
Scanner.nextInt()
和Scanner.hasNextInt()
并避免解析它。
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