[英]How to remove duplicates in mongoDB with mongoose(NodeJS)
I have a collection in MongoDB where there are around (~200k records).我在 MongoDB 有一个集合,其中大约有(约 20 万条记录)。 My sample record would look like,我的样本记录看起来像,
{
name:String,
slug:String,
metaDes:String,
content:String,
parentID:String,
thumbnail:String,
display:Boolean,
}
I am having a lot of duplicate records in the collection having same slug
我在集合中有很多重复的记录有相同的slug
I want to remove duplicate records based on slug
Is there any fast way to remove all duplicates with mongoose(Nodejs)?我想根据slug
删除重复记录有没有什么快速的方法可以用 mongoose(Nodejs) 删除所有重复项? Thanks!谢谢!
Remove duplicate records in the collection having the same slug
删除集合中具有相同slug
的重复记录
db.table.aggregate([ { "$group": { _id: {slug: "$slug"}, slugs: { $addToSet: "$_id" }, count: { $sum: 1 } } }, { "$match": { count: { "$gt": 1 } } } ]).forEach(function(doc) { doc.slugs.shift(); db.table.remove({ _id: {$in: doc.slugs} }); })
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