如何使用正则表达式特定字符串拆分字符串

Question

I have a value(String) like "BLD00000001BLD00000002 BLD00000003, BLD00000004".

I want to use Regex """^BLD\d{8}"""

but it didn't work..

I want to return results like (BLD00000001','BLD00000002','BLD00000003... )

        var regex = Regex("""[\{\}\[\]\/?.,;:|\) *~`!^\-_+<>@\#$%&\\\=\(\'\"]""")
        val cvrtBldIds = bldIds.split(regex)

        if (cvrtBldIds.joinToString(separator="").length % 11 != 0) {
            throw BadRequestException("MSG000343", listOf("빌딩Id", "BLD[숫자8자리]"))
        } else {
            val res = cvrtBldIds
                .filter{it.startsWith("BLD")}   // BLD로 시작하는 것만 추출
                .joinToString(separator = "','")      // 아이디 앞뒤로 ',' 붙이기 
            bldIds = res
            var sb = StringBuffer()
            sb.append("'")
            sb.append(bldIds)
            sb.append("'")
            input.bldId = sb.toString()
        }

Answer 1

Do it as follows:

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    public static void main(String[] args) {
        String str = "BLD00000001BLD00000002 BLD00000003, BLD00000004";
        List<String> list = new ArrayList<String>();
        Pattern pattern = Pattern.compile("BLD\\d{8}");
        Matcher matcher = pattern.matcher(str);
        while (matcher.find()) {
            list.add(matcher.group());
        }
        System.out.println(list);
    }
}

Output:

[BLD00000001, BLD00000002, BLD00000003, BLD00000004]

Notes:

1. BLD\\d{8} means starting with BLD and then 8 digits.
2. Java regex tutorial: https://docs.oracle.com/javase/tutorial/essential/regex/

Answer 2

Seems you want to split on a space, or a comma-space combo, or between a digit and the text BLD . The following regex can do that:

,?\s|(?<=\d)(?=BLD)

See regex101 for demo.

Answer 3

Here is how you can extract BLD\d{8} pattern matches in Kotlin using .findall() :

val text = """"BLD00000001BLD00000002 BLD00000003, BLD00000004"."""
val matcher = """BLD\d{8}""".toRegex()
println(matcher.findAll(text).map{it.value}.toList() )
// => [BLD00000001, BLD00000002, BLD00000003, BLD00000004]

See the Kotlin demo