Pyautogui：具有图像识别功能的自动点击器如何制作仅在识别图像时才运行的 function？

Question

I'm new in python and I know my code is really messy. I need help, I wanted the function below to only run If an Image I set is recognised mc_ok_button.png but it's kind of confusing because I want it to join with a loop I already made. If I place the code in the loop wouldn't it not run the rest of the functions below it?

My image recognition function:

import pyautogui as pg
import pydirectinput as pd
import time

ax,ay = pg.locateCenterOnScreen('mc_ok_button.png',confidence=.6)

def function_when_restart():
    print(ax,ay)
    pd.click(ax,ay)
    print('Waiting to return back to the server...')
    time.sleep(8)
    pd.moveTo(892,531)
    print('finding server...')
    pd.click()
    print('connecting to the server...')

function_when_restart()

Then I want the function_when_restart() function to only run if the mc_ok_button.png image is recognised and make project() and fix_tool() stop while function_when_restart() is running then continue back to make project() and fix_tool() :

from time import monotonic
from time import monotonic, sleep

start = monotonic()
        while monotonic() - start < (60) : #Run for exactly 1 minute
            # I want the image recognition to always run and if the image pops up I want 
            project()
            sleep(5)
            fix_tool()

Answer 1

below can help?

while True:
     image = pyautogui.locateOnScreen('image.png')
     if image != None:
         project()
         sleep(5)
         fix_tool()
     else:
        pass