[英]Regex to accept only 7 types of special characters
In my react-native application, I have a requirement to accept 7 types of special characters in a string.在我的 react-native 应用程序中,我需要在一个字符串中接受 7 种特殊字符。 It could be all 7, few of them or none of them.可能是全部 7 个,其中很少或没有。
Special characters are (),@'/-
特殊字符为(),@'/-
so the accepted string will be like following.所以接受的字符串将如下所示。
ABcd()ef,/'-@sdf
=> accepting all 7 ABcd()ef,/'-@sdf
=> 接受所有 7ABcd(),
=> accepting few of 7 ABcd(),
=> 接受 7 个中的几个ABcddfg
=> accepting none of 7 ABcddfg
=> 不接受 7How should I write this regex in java script?我应该如何在 java 脚本中编写这个正则表达式?
Perhaps you mean也许你的意思是
https://regex101.com/r/Vt9wmF/1 https://regex101.com/r/Vt9wmF/1
/[\w\(\),@'\/-]/g
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