Sed 没有替换所有出现的点和正斜杠

Question

I've got $dir which holds a string like ./Account/ where the word 'Account' can be any word (eg App, Home, etc).

I want to get rid of the . and both occurrences of / to wind up with just Account . Here's the pattern I'm using: sed 's/\.\///g' .

This is the string I'm applying it on:

"import React from 'react';

const $(echo $dir | sed 's/\.\///g') = () => (
  <div>
    <h1>App</h1>
  </div>
);

export default App;"

The . and first / is removed from the output but it still has the second occurrence of the / .

Output:

import React from 'react';

const Account/ = () => (
  <div>
    <h1>App</h1>
  </div>
);

export default App;

How can I make it so that even the second / is removed?

Answer 1

sed 's/\.\///g'

That removes every ./ , not every . and / .

You want

sed 's|[/.]||g'

Using | instead of / as delimiter is a good idea to avoid the need to escape / .

Example:

$ sed 's|[/.]||g' <<< './Account/'
Account

Answer 2

You may use

$(echo $dir | sed 's,\./\([^/]*\)/,\1,g')

The regex delimiters are changed to , so as not to have to escape slashes.

Details

• \./ - ./ substring
• \([^/]*\) - Group 1 (later referred to with \1 placeholder from RHS): any 0 or more chars other than /
• / - a / char.

Answer 3

You're searching for the string ./ , whereas you want to be searching for either a . or a / .

Replace the search string with the character class [\/.] like so:

echo "./Account/" | sed 's/[\/.]//g'

output:

Account

Answer 4

Use two substitutions to remove ./ from the beginning and / from the end of $dir .

echo "$dir" | sed 's|^\./||; s|/$||'