R 正则表达式 / grep / grepl 用于字母后跟破折号和数字

Question

I'm trying to find the right grep notation to identify strings that have this pattern: Any number of letters followed by a dash (-) followed by any number of numbers. For example ABC-123 would be a fit while 123-ABC or A1-B2 would not.

I've tried grepl('[[A:Za:z]]\\-[[0:9]]','ABC-123') but am not getting the correct results.

Any suggestions?

Answer 1

We can change the range ( : ) to - and instead of [[ . In the pattern, we also specify the ^ and $ for start and end of string respectively. The + for letters and digits specify one or more...

grepl("^[A-Za-z]+-[0-9]+$", str1)
#[1]  TRUE FALSE FALSE

Or if we want to use [[ ,

grepl("^[[:alpha:]]+-\\d+$", str1)
#[1]  TRUE FALSE FALSE

data

str1 <- c("ABC-123", "123-ABC", "A1-B2")