[英]How to pass(i mean display) the index value of <li></li>(under <ol></ol> default type) to <p></p> if <p></p> is inside of that said <li></li>?
What I want to achieve here is to display the value of the index of < li >< /li > (under < ol >< /ol > default type) to the < p >< /p >(could be one of more, most likely just one) inside it.我这里要实现的是将<li></li>(在<ol></ol>默认类型下)的索引值显示到<p></p>(可以是多个,很可能只有一个)在里面。
MY INITIAL CODE:我的初始代码:
<ol>
<li>
<p>First p element in div.</p>
</li>
<li>
<span>Second p</span>
</li>
<li>
<p>A third p element in div.</p>
</li>
<li>
<p>A fourth p element in div.</p>
</li>
</ol>
SCRIPT:脚本:
<script>
var x = document.getElementsByTagName('li');
var y = document.getElementsByTagName('p');
for(var j = 0; j < x.length; j++){
for(var k = 0; k < y.length; k++) {
if(x[j].index == y[k].index){
y[j].innerHTML = j+1;
}
}
}
</script>
OUTPUT: OUTPUT:
1.1
2.Second p
3.2
4.3
EXPECTED OUTPUT:预期 OUTPUT:
1.1
2.Second p
3.3
4.4
In your code, both x[j].index and y[k].index are undefined.在您的代码中, x[j].index 和 y[k].index 都未定义。 What do you expect to happen when this occurs?当这种情况发生时,您预计会发生什么?
I recommend using querySelectorAll
instead of getElementsByTagName
- more precise.我建议使用querySelectorAll
而不是getElementsByTagName
- 更准确。 Then don't get all p
elements in the document;然后不要获取文档中的所有p
元素; just get all p
elements in each li
.只需获取每个li
中的所有p
元素。 Probably a more elegant way to do this but the nested loop approach works:可能是一种更优雅的方法,但嵌套循环方法有效:
var li = document.querySelectorAll('ol li'); for(var i = 0; i < li.length; i++) { var p = li[i].querySelectorAll('p'); for(var j = 0; j < p.length; j++) { p[j].innerHTML = i + 1; } }
<ol> <li> <p>First p element in div.</p> </li> <li> <span>Second p</span> </li> <li> <p>A third p element in div.</p> </li> <li> <p>A fourth p element in div.</p> </li> </ol>
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