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如何使用 JOIN 运算符正确回显 SQL 表中的结果?

[英]How to echo results from SQL table correctly using JOIN operator?

I have two tables:我有两张桌子:

Clubs俱乐部

    |---------------------|------------------|
    |          id         |       name       |
    |---------------------|------------------|
    |           1         |      Arsenal     |
    |---------------------|------------------|
    |           2         |      Chelsea     |
    |---------------------|------------------|
    |           3         |      Fulham      |
    |---------------------|------------------|
    |           4         |      Leeds       |
    |---------------------|------------------|

Matches火柴

    |---------------------|------------------|------------------|
    |          id         |       home       |        away      |
    |---------------------|------------------|------------------|
    |           1         |        1         |         3        |
    |---------------------|------------------|------------------|
    |           2         |        2         |         4        |
    |---------------------|------------------|------------------|

Explanation: the numbers in the columns "home" and "away" in the Matches table linking to the the id in de Clubs table.解释: Matches 表中“home”和“away”列中的数字链接到 de Clubs 表中的 id。

Now I want to echo (with php) the following:现在我想回显(使用 php)以下内容:

|---------------------|------------------|
|          home       |       away       |
|---------------------|------------------|
|         Arsenal     |      Fulham      |
|---------------------|------------------|
|         Chelsea     |       Leeds      |
|---------------------|------------------|

Explanation: when clicking on the teamname I want to open the club.php page with the teaminfo.说明:点击球队名称时,我想打开带有球队信息的俱乐部。php 页面。

I've tried the following:我尝试了以下方法:

<?php
$sql = "SELECT * FROM matches JOIN clubs ON matches.home AND matches.away = clubs.id"
$rs_result = $conn->query($sql);
?> 

<div style="overflow-x:auto">
<table>
<tr><th><strong>Home</strong></th><th><strong>Away</strong></th><tr>

<?php     
while($row = $rs_result->fetch_assoc()) {
?> 

<tr>
<td><a href="club.php?id=<?php echo $row['home'];?>"><? echo $row['home']; ?></a></td>
<td><a href="club.php?id=<?php echo $row['away'];?>"><? echo $row['away']; ?></a></td>
</tr>

<?php } ?>  
</table></div>

It is echoing the following:它呼应了以下内容:

|---------------------|------------------|
|          home       |       away       |
|---------------------|------------------|
|           1         |         3        |
|---------------------|------------------|
|           2         |         4        |
|---------------------|------------------|

My question: How can I show the clubnames in the table but passing the club id in the "a href" link?我的问题:如何在表格中显示俱乐部名称,但在“a href”链接中传递俱乐部 ID? I've tried $row[1] and so on but it doesnt work.我试过 $row[1] 等等,但它不起作用。 Which SQL statement do I need?我需要哪个 SQL 声明? JOIN?加入? INNER JOIN?内部联接? LEFT JOIN?左加入?

Many thanks in advance!提前谢谢了!

I believe this should work - I made an adjustment to your query.我相信这应该可行 - 我对您的查询进行了调整。 You can use left joins when you are interested in the left side of the query (matches) and do not care if the clubs have not been populated.当您对查询的左侧(匹配项)感兴趣并且不关心是否尚未填充俱乐部时,您可以使用左连接。 F ex if you have a home - away of 1 and 5. We know that 1 is Arsenal but there is no entry for 5 in clubs. F ex,如果您有 1 和 5 的主客场。我们知道 1 是阿森纳,但在俱乐部中没有 5 的条目。 Left join will display it, inner join will not.左连接会显示它,内连接不会。

<?php
$sql = "SELECT home,away,homeclub.name as homename,awayclub.name  as awayname FROM matches 
JOIN clubs as homeclub ON matches.home = homeclub.id
JOIN clubs as awayclub ON matches.away = awayclub.id"
$rs_result = $conn->query($sql);
?> 

<div style="overflow-x:auto">
<table>
<tr><th><strong>Home</strong></th><th><strong>Away</strong></th><tr>

<?php     
while($row = $rs_result->fetch_assoc()) {
?> 

<tr>
<td><a href="club.php?id=<?php echo $row['home'];?>"><? echo $row['homename']; ?></a></td>
<td><a href="club.php?id=<?php echo $row['away'];?>"><? echo $row['awayname']; ?></a></td>
</tr>

<?php } ?>  
</table>
</div>

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