[英]Comparing php value with javascript variable?
I am working on php and javascript project.我正在研究 php 和 javascript 项目。 I just want to compare echo return value of php with javascript variable.
我只想将 php 的回声返回值与 javascript 变量进行比较。
php backend code which returns 'no' using echo php 使用回显返回“否”的后端代码
if($connection){
$sql ="SELECT secondname FROM account WHERE email = '$email' && password = '$password'";
$searchquery = mysqli_query($connection, $sql);
if(!(mysqli_num_rows($searchquery) == 0)) {
$row = mysqli_fetch_array($searchquery);
$secondname = $row['secondname'];
echo $secondname ;
} else {
echo 'no';
}
Now comparing with javascript variable现在与 javascript 变量进行比较
$.post("signnin.php",{
email: email,
password: password,
},
function(data, status){
if(data == 'no'){
console.log('same');
}else{
console.log('not same');
}
});
it give same result if value are same or not.如果值相同或不同,它会给出相同的结果。 i also JSON.stringify but it still not working
我也 JSON.stringify 但它仍然无法正常工作
The output from the URL probably includes white space. URL 中的 output 可能包含空格。
JSON is a good way to normalize that, but you need to apply it at the PHP end, not the JavaScript end. JSON 是对其进行规范化的好方法,但您需要在 PHP 端应用它,而不是在 JavaScript 端应用它。
$secondname = $row['secondname'];
header("Content-Type: application/json");
echo json_encode([ "secondname" => $secondname ]);
} else {
header("Content-Type: application/json");
echo json_encode([ "failure" => "Login failed" ]);
}
and then:接着:
$.post(
"signnin.php",
{ email, password },
function(data, status){
if(data.failure){
console.log('same');
} else {
console.log('not same');
}
}
);
You are probably sending whitespaces in your PHP script.您可能在 PHP 脚本中发送空格。 There are 2 ways to solve this -
有两种方法可以解决这个问题 -
Ensure that you put the starting php tag from the very first line and don't put the ending php tag (?>).确保从第一行开始放置 php 标记,并且不要放置结束 php 标记 (?>)。
Instead of comparing texts, compare numbers.与其比较文本,不如比较数字。 In php script echo 1 and in js compare data==1.
在 php 脚本中 echo 1 和 js 中比较数据==1。 This way whitespaces are automatically ignored.
这样空格会被自动忽略。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.