尝试按搜索词搜索数组时忽略过滤器 function

Question

I'm attempting to write a similar function to this to filter a large array based on a search term:

function my_func(my_list, term) {
    my_list.filter(function(card){
    if(card.includes(term)){
        return card;
    }
    else {
      return  "something else"
    }
    })
  return "inside"
}

const my_list = ["merloc", "spider", "orc",  "wisp", "giant"]

my_func(my_list, "wisp")

However card is never returned. In fact not even "something else" is returned - the only result is "inside". How can I get the above function to return card based on the search term?

Answer 1

A small fix add return before my_list.filter

function my_func(my_list, term) {
  return my_list.filter(function(card){
    if(card.includes(term)){
       return card;
    }
    else {
       return  "something else"
    }
 })
 return "inside"
}

const my_list = ["merloc", "spider", "orc",  "wisp", "giant"]

my_func(my_list, "wisp")