如何对布尔对象列表进行逻辑和操作？

Question

I have a list of bool objects list like this:

[[True, True, True, False], [False, True, True, False], [False, False, True, True]]

I want to bit and those lists and get the result:

[False, False, True, False]

What is the best way to do this?

Answer 1

As long as you use boolean, you could zip and then use all :

data = [[True, True, True, False], [False, True, True, False], [False, False, True, True]]
result = [all(e) for e in zip(*data)]
print(result)

Output

[False, False, True, False]

Answer 2

You can use functools.reduce and the bitwise "and" operator.and_ , as well as the typical zip(*...) transposition pattern:

from functools import reduce
from operator import and_

lst = [[True, True, True, False], [False, True, True, False], [False, False, True, True]]

[reduce(and_, x) for x in zip(*lst)]
# [False, False, True, False]

Answer 3

If you want to specifically use the bitwise & operator, then you can use functools.reduce with zip :

>>> from functools import reduce
>>> l = [[True, True, True, False], [False, True, True, False], [False, False, True, True]]
>>> [reduce(lambda x, y: x & y, lst) for lst in zip(*l)]
[False, False, True, False]

We can also create our own mini function to replace lambda :

>>> def bitwise_and(x, y):
...     return x & y
...
>>> [reduce(bitwise_and, lst) for lst in zip(*l)]
[False, False, True, False]

Or just use the operator module, as shown in @schwobaseggl's answer.