骆驼：将 json 阵列解组为 pojo object

Question

I'm working with camel-spring, I have Json array as a response from an api as below:

[{"userName":"name","email":"email"}]

my object like this:

public class Response{

private String userName;
private String email;

setters & getters
}

my route builder:

from("seda:rout")
.routeId("distinaation")
          .unmarshal()
          .json(JsonLibrary.Jackson, Request.class)
          .bean(Bean.class, "processRequest")
          .to(destination)
          .unmarshal()
          .json(JsonLibrary.Jackson, Response.class)
          .bean(Bean.class, "processResponse")

error:

Can not desserialize instance of com.liena.Response out of START_ARRAY token

is there any way to unmarshall json array directly to my obj??

Answer 1

I solved the problem by using object mapper in my processor.

my route builder:

from("seda:rout")
.routeId("distinaation")
          .unmarshal()
          .json(JsonLibrary.Jackson, Request.class)
          .bean(Bean.class, "processRequest")
          .to(destination)
          .bean(Bean.class, "processResponse")

processor:

public Response processResponse(Exchange exchange) throws IOException {
        String responseStr = exchange.getIn().getBody().toString();
        ObjectMapper mapper = new ObjectMapper();
        List<Response> list = mapper.readValue(responseStr, new TypeReference<List<Response>>({});
        Response response = list.get(0);
        ...}

Another short way to do this will be: in route builder:

from("seda:rout")
.routeId("distinaation")
          .unmarshal()
          .json(JsonLibrary.Jackson, Request.class)
          .bean(Bean.class, "processRequest")
          .to(destination)
          .unmarshal(new ListJacksonDataFormat(Response.class))
          .bean(Bean.class, "processResponse")

processor:

public Response processResponse(List<Response> list {
       Response response = list.get(0);
       ...
}