嵌套的 Future.sequence 顺序执行包含的 Futures

Question

I have a future( doFour ) that is executed and results passed to a flatmap. Inside the flatmap I execute two more future( doOne and doTwo ) functions expecting them to run on parallel but I see they are running sequentially (2.13). Scastie

Why are doOne and doTwo not execute in parallel?

How can I have them to run in parallel?

import scala.concurrent.ExecutionContext.Implicits.global
import scala.concurrent.duration.Duration
import scala.concurrent.{Await, Future}

object Test {
  def doOne(): Future[Unit] = Future {
    println("startFirst");      Thread.sleep(3000);     println("stopFirst")
  }

  def doTwo(): Future[Unit] = Future {
    println("startSecond");      Thread.sleep(1000);      println("stopSecond")
  }


  def doFour(): Future[Unit] = Future {
    println("do 4");     Thread.sleep(1000);     println("done 4")

  }


  def main(args: Array[String]) {


    val resOut = doFour().flatMap { a =>

      val futureOperations = Seq(doOne(), doTwo())

      val res = Future.sequence(futureOperations)
      res
    }

    val stream = Await.result(resOut, Duration.Inf)
  }
}

Answer 1

A Future becomes eligible for execution as soon as it is created. So this line creates two Futures that can potentially be executed:

val futureOperations = Seq(doOne(), doTwo())

The call to Future.sequence will create a new Future that waits for each of the futures to complete in turn, but they will both already be available for execution by this point in the code.

val res = Future.sequence(futureOperations)

If you want Future s to start sequentially you need to use map/flatMap :

val res = doOne().map( _ => doTwo())

With this code doTwo will not be called until doOne completes (and not at all if doOne fails)

The reason that this does not appear to happen in your example is that you are calling a blocking operation in your Future which is blocking a thread that would otherwise be used to execute other Future s. So although there are two Future s available for execution, only one is actually being executed at a time.

If you mark the code as blocking it works correctly:

import scala.concurrent.blocking

def doOne(): Future[Unit] = Future {
  blocking{println("startFirst");      Thread.sleep(3000);     println("stop First")}
}

def doTwo(): Future[Unit] = Future {
  blocking{println("startSecond");      Thread.sleep(1000);      println("stop Second")}
}

See the comments section for details of why the default behaviour is different on different versions, and why you should never make assumptions about the relative execution order of independent Future s.