如何将日期拆分为日、月和年

Question

I have a date in this format - 31Jan2020 , how do I get the day, month and year - 31, Jan and 2020.

I am looping through a dataframe and the name of the date column is date . This is what I am doing

for index,row in data.iterrows():
    date = row['date']
    print(date)

Answer 1

The code below should work in Python:

import datetime as dt
import pandas as pd

date_str = '31Jan2020'

a_date = dt.datetime.strptime(date_str, '%d%b%Y').date()

print(a_date.year)
print(a_date.month)
print(a_date.day)

data_df = pd.DataFrame([['31Jan2020'], ['1Jan2020']], columns=['date_str'])

data_df['year'] = data_df['date_str'].map(lambda x: dt.datetime.strptime(x, '%d%b%Y').date().year)
data_df['month'] = data_df['date_str'].map(lambda x: dt.datetime.strptime(x, '%d%b%Y').date().month)
data_df['day'] = data_df['date_str'].map(lambda x: dt.datetime.strptime(x, '%d%b%Y').date().day)

print(data_df)